Problem
collections.namedtuple()
Basically, namedtuples are easy to create, lightweight object types.
They turn tuples into convenient containers for simple tasks.
With namedtuples, you don’t have to use integer indices for accessing members of a tuple.
Example
Code 01
>>> from collections import namedtuple>>> Point = namedtuple('Point','x,y')>>> pt1 = Point(1,2)>>> pt2 = Point(3,4)>>> dot_product = ( pt1.x * pt2.x ) +( pt1.y * pt2.y )>>> print dot_product11
Code 02
>>> from collections import namedtuple>>> Car = namedtuple('Car','Price Mileage Colour Class')>>> xyz = Car(Price = 100000, Mileage = 30, Colour = 'Cyan', Class = 'Y')>>> print xyzCar(Price=100000, Mileage=30, Colour='Cyan', Class='Y')>>> print xyz.ClassY
Task
Dr. John Wesley has a spreadsheet containing a list of student’s IDs, marks, class and name.
Your task is to help Dr. Wesley calculate the average marks of the students.
Note:
- Columns can be in any order. IDs, marks, class and name can be written in any order in the spreadsheet.
- Column names are
ID
,MARKS
,CLASS
andNAME
. (The spelling and case type of these names won’t change.)
Input Format
The first line contains an integer N, the total number of students.
The second line contains the names of the columns in any order.
The next N lines contains the marks, IDs, name and class, under their respective column names.
Constraints
0 < N ≤ 100
Output Format
Print the average marks of the list corrected to 2 decimal places.
Sample Input
Testcae 01
5ID MARKS NAME CLASS 1 97 Raymond 7 2 50 Steven 4 3 91 Adrian 9 4 72 Stewart 5 5 80 Peter 6
TESTCASE 02
5MARKS CLASS NAME ID 92 2 Calum 1 82 5 Scott 2 94 2 Jason 3 55 8 Glenn 4 82 2 Fergus 5
Sample Output
TESTCASE 01
78.00
TESTCASE 02
81.00
Explanation
TESTCASE 01
Average = (97 + 50 + 91 + 72 + 80)/5
Can you solve this challenge in 4 lines of code or less
?
NOTE: There is no penalty
for solutions that are correct but have more than 4 lines
Solution – Collections.namedtuple() In Python
n = int(input())cols = input().split()details = [input().split() for _ in range(n)]mark = cols.index("MARKS")sum = 0for i in details: sum += int(i[mark]) print(round(sum/n, 2))
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