Finding The Percentage HackerRank Solution In Python

Problem

The provided code stub will read in a dictionary containing key/value pairs of name:[marks] for a list of students. Print the average of the marks array for the student name provided, showing 2 places after the decimal.

Example

marks key:value pairs are

‘alpha’: [20, 30, 40]

‘beta’: [30, 50, 70]

query_name = ‘beta’

The query_name is ‘beta’. beta’s average score is (30 + 50 + 70)/3 = 50.0.

Input Format

The first line contains the integer n, the number of students’ records. The next  lines contain the names and marks obtained by a student, each value separated by a space. The final line contains query_name, the name of a student to query.

Constraints

• 2 ≤ n ≤ 10
• 0 ≤ marks[i] ≤ 100
• length of marks arrays = 3

Output Format

Print one line: The average of the marks obtained by the particular student correct to 2 decimal places.

Sample Input 0

3
Krishna 67 68 69
Arjun 70 98 63
Malika 52 56 60
Malika

Sample Output0

56.00

Explanation 0

Marks for Malika are {52, 56, 60} whose average is (52 + 56+60)/3 ==> 56

Sample Input 1

2
Harsh 25 26.5 28
Anurag 26 28 30
Harsh

Sample Output 1

26.50

Soltion to HackerRank Find The Percentage In Python

In this problem, we are to print the average score of the student provided in the last input.

if __name__ == '__main__':    n = int(input())    student_marks = {}    for _ in range(n):        name, *line = input().split()        scores = list(map(float, line))        student_marks[name] = scores    query_name = input()    average = sum(student_marks[query_name])/3    print(format(average, '.2f'))