Words Score HackerRank Solution In Python

Problem

In this challenge, the task is to debug the existing code to successfully execute all provided test files.

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Consider that vowels in the alphabet are a, e, i, o, u and y.

Function score_words takes a list of lowercase words as an argument and returns a score as follows:

The score of a single word is  if the word contains an even number of vowels. Otherwise, the score of this word is 1. The score for the whole list of words is the sum of scores of all words in the list.

Debug the given function score_words such that it returns a correct score.

Your function will be tested on several cases by the locked template code.

Input Format

The input is read by the provided locked code template. In the first line, there is a single integer n denoting the number of words. In the second line, there are n space-separated lowercase words.

Constraints

• 1 ≤ n ≤ 20
• Each word has at most 20 letters and all letters are English lowercase letters.

Output Format

The output is produced by the provided and locked code template. It calls function score_words with the list of words read from the input as the argument and prints the returned score to the output.

Sample Input 0

2hacker book

Sample Output 0

4

Explanation 0

There are two words in the input: hacker and book. The score of the word hacker is 2 because it contains an even number of vowels, i.e. 2 vowels, and the score of book is 2 for the same reason. Thus the total score is 2 + 2 = 4.

Sample Input 1

3programming is awesome

Sample Output 1

4

Explanation 1

There are 3 words in the input: programming, is and awesome. The score of programming is 1 since it contains 3 vowels, an odd number of vowels. The score of is is also 1 because it has an odd number of vowels. The score of awesome is 2 since it contains 4 vowels, an even number of vowels. Thus, the total score is 1 + 1 + 2 = 4.

Solution to Words Score HackerRank In Python

In this problem, we are to verify whether, the number of vowels in each words of a given sentence is odd or even. If it is odd, then the score of that particular word is 1, while 2 if it’s even. The total score of a given sentence is the sum of the score of each words.

Note: In this problem, we were given locked code template that we are just to debug and correct any error in it.

def is_vowel(letter):    return letter in ['a', 'e', 'i', 'o', 'u', 'y']def score_words(words):    score = 0    for word in words:        num_vowels = 0        for letter in word:            if is_vowel(letter):                num_vowels += 1        if num_vowels % 2 == 0:            score += 2        else:            score += 1    return scoren = int(input())words = input().split()print(score_words(words))