Zipped! HackerRank Solution In Python

Problem

zip([iterable, …])

This function returns a list of tuples. The i^th tuple contains the i^th element from each of the argument sequences or iterables.

If the argument sequences are of unequal lengths, then the returned list is truncated to the length of the shortest argument sequence.

Sample Code

>>> print zip([1,2,3,4,5,6],'Hacker')[(1, 'H'), (2, 'a'), (3, 'c'), (4, 'k'), (5, 'e'), (6, 'r')]>>> >>> print zip([1,2,3,4,5,6],[0,9,8,7,6,5,4,3,2,1])[(1, 0), (2, 9), (3, 8), (4, 7), (5, 6), (6, 5)]>>> >>> A = [1,2,3]>>> B = [6,5,4]>>> C = [7,8,9]>>> X = [A] + [B] + [C]>>> >>> print zip(*X)[(1, 6, 7), (2, 5, 8), (3, 4, 9)]

Task

The National University conducts an examination of N students in X subjects.
Your task is to compute the average scores of each student.

The format for the general mark sheet is:

Student ID → ___1_____2_____3_____4_____5__               Subject 1   |  89    90    78    93    80Subject 2   |  90    91    85    88    86  Subject 3   |  91    92    83    89    90.5            |______________________________Average        90    91    82    90    85.5 

Input Format

The first line contains N and X separated by a space.
The next X lines contains the space separated marks obtained by students in a particular subject.

Constraints

0 < N ≤ 100

0 < X ≤ 100

Output Format

Print the averages of all students on separate lines.

The averages must be correct up to 1 decimal place.

Sample Input

5 389 90 78 93 8090 91 85 88 86  91 92 83 89 90.5

Sample Output

90.0 91.0 82.0 90.0 85.5   

Explanation

Marks obtained by student 1: 89, 90, 91
Average marks of student 1: 270/3 = 90

Marks obtained by student 2: 90, 91, 92
Average marks of student 2: 273/3 = 91

Marks obtained by student 3: 78, 85, 83
Average marks of student 3: 246/3 = 82

Marks obtained by student 4: 93, 88, 89
Average marks of student 4: 270/3 = 90

Marks obtained by student 5: 80, 86, 90.5
Average marks of student 5: 256.5/3 = 85.5

Solution – Zipped!

x, y = list(map(int, input().split()))scores = [list(map(float, input().split())) for _ in range(y)]for i in zip(*scores):    print(sum(i)/len(i))

NOTE: The problem solved above, Zipped!, was generated by HackerRank and the solution was brought by the admin of  CodingSolutions for educational purpose. Got any issues with the code? Ask your questions in the comment box and I shall attend to it.