Decorators 2 - Name Directory HackerRank Solution In Python

Problem

Let’s use decorators to build a name directory! You are given some information about  people. Each person has a first name, last name, age and sex. Print their names in a specific format sorted by their age in ascending order i.e. the youngest person’s name should be printed first. For two people of the same age, print them in the order of their input.

For Henry Davids, the output should be:

Mr. Henry Davids

For Mary George, the output should be:

Ms. Mary George

Input Format

The first line contains the integer N, the number of people.
 lines follow each containing the space separated values of the first name, last name, age and sex, respectively.

Constraints

1 ≤ N ≤ 10

Output Format

Output N names on separate lines in the format described above in ascending order of age.

Sample Input

3Mike Thomson 20 MRobert Bustle 32 MAndria Bustle 30 F

Sample Output

Mr. Mike ThomsonMs. Andria BustleMr. Robert Bustle

Concept

For sorting a nested list based on some parameter, you can use the itemgetter library. You can read more about it here.

Solution – Decorators 2 – Name Directory In Python | HackerRank

import operatordef person_lister(f):    def inner(people):        return map(f, sorted(people, key=lambda x: int(x[2])))        # complete the function    return inner@person_listerdef name_format(person):    return ("Mr. " if person[3] == "M" else "Ms. ") + person[0] + " " + person[1]if __name__ == '__main__':    people = [input().split() for i in range(int(input()))]    print(*name_format(people), sep='\n')