collections.Counter() HackerRank Solution

Problem

collections.Counter()

A counter is a container that stores elements as dictionary keys, and their counts are stored as dictionary values.

Sample Code

>>> from collections import Counter>>> >>> myList = [1,1,2,3,4,5,3,2,3,4,2,1,2,3]>>> print Counter(myList)Counter({2: 4, 3: 4, 1: 3, 4: 2, 5: 1})>>>>>> print Counter(myList).items()[(1, 3), (2, 4), (3, 4), (4, 2), (5, 1)]>>> >>> print Counter(myList).keys()[1, 2, 3, 4, 5]>>> >>> print Counter(myList).values()[3, 4, 4, 2, 1]

Task

Raghu is a shoe shop owner. His shop has X number of shoes.

He has a list containing the size of each shoe he has in his shop.

There are N number of customers who are willing to pay x_i amount of money only if they get the shoe of their desired size.

Your task is to compute how much money Raghu earned.

Input Format

The first line contains X, the number of shoes.

The second line contains the space separated list of all the shoe sizes in the shop.

The third line contains N, the number of customers.

The next N lines contain the space separated values of the shoe size desired by the customer and x_i, the price of the shoe.

Constraints

0 < X < 10³

0 < N ≤ 10³

20 < x_i < 100

2 < shoe size < 20

Output Format

Print the amount of money earned by Raghu.

Sample Format

102 3 4 5 6 8 7 6 5 1866 556 456 554 4018 6010 50

Sample Output

200

Explanation

Customer 1: Purchased size 6 shoe for $55.

Customer 2: Purchased size 6 shoe for $45.

Customer 3: Size 6 no longer available, so no purchase.

Customer 4: Purchased size 4 shoe for $40.

Customer 5: Purchased size 18 shoe for $60.

Customer 6: Size 10 not available, so no purchase.

Total money earned =  55 + 45 + 40 + 60 = $200

Solution to HackerRankcollections.Counter() in Python

In this problem, we are to calculate the amount earned by the man after he has as delivered all deliverables.

In this problem, we are to calculate the amount earned by the man after he has as delivered all deliverables.

from collections import Counterx = int(input())lst = Counter(map(int, input().split()))n = int(input())cus = list()for _ in range(n):    cus.append(map(int, input().split()))profit = 0for size, amount in cus:    if lst[int(size)] > 0:        lst[int(size)] -= 1        profit += int(amount)    else:        continueprint(profit)